Display HTML content from a resource in your application
-
Import the required classes and interfaces.
import net.rim.device.api.browser.field2.*;
import net.rim.device.api.system.*;
import net.rim.device.api.ui.*;
import net.rim.device.api.ui.container.*;
-
Create the application framework by extending the
UiApplication class. In
main(), create an instance of the new class and
invoke
enterEventDispatcher() to enable the application to
receive events. In the application constructor, invoke
pushScreen() to display the custom screen for the
application. The
BrowserFieldDemoScreen class, described in step 3,
represents the custom screen.
public class BrowserFieldDemo extends UiApplication
{
public static void main(String[] args)
{
BrowserFieldDemo app = new BrowserFieldDemo();
app.enterEventDispatcher();
}
public BrowserFieldDemo()
{
pushScreen(new BrowserFieldDemoScreen());
}
}
-
Create the custom screen by extending the
MainScreen class.
class BrowserFieldDemoScreen extends MainScreen
{
public BrowserFieldDemoScreen()
{
}
}
-
In the screen constructor, create an instance of the
BrowserField class.
BrowserField myBrowserField = new BrowserField();
-
In the screen constructor, invoke
add() to add the
BrowserField object to the screen.
add(myBrowserField);
-
In the screen constructor, invoke
BrowserField.requestContent() to specify the
location of the resource in your application and display the HTML content.
myBrowserField.requestContent("local:///test.jsp");
Note: The BrowserField class does not access resources using a folder
structure. The
BrowserField class displays the first resource
found that matches the specifed file name.
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